(1/16)^3x=64^x-4

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Solution for (1/16)^3x=64^x-4 equation: 



(1/16)^3x=64^x-4

We move all terms to the left:

(1/16)^3x-(64^x-4)=0



Domain of the equation: 16)^3x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/16)^3x-(64^x-4)=0

We get rid of parentheses

(+1/16)^3x-64^x+4=0

We multiply all the terms by the denominator


(+1-64^x*16)^3x+4*16)^3x=0

Wy multiply elements

(+1-64^x*16)^3x+64x=0

We add all the numbers together, and all the variables

64x+(+1-64^x*16)^3x=0

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